Enjaych
Enjaych
20-04-2017
Mathematics
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I need help finding out this question
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j4cek
j4cek
20-04-2017
[tex]\log_4\dfrac{1}{64}=\log_4 64^{-1}=\log_4 \left(4^3\right)^{-1}=\log_4 4^{-3}=-3\cdot \log_4 4=\boxed{-3}[/tex]
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