OodleDoodle
OodleDoodle OodleDoodle
  • 21-04-2017
  • Mathematics
contestada

3n^2-n over n^2-1 / n^2 over n+1

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Аноним Аноним
  • 21-04-2017
4-1/n^3

I hope this helps. 

Have a "AWESOME" day. :)
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catalinacastil1
catalinacastil1 catalinacastil1
  • 03-02-2021

Answer:

Step-by-step explanation:

3n^-n over n^2-1 * n^2 over n+1

Nx(3n-1) over (n-1) x (n+1) * N+1 over N^2

3N-1 over Nx(n-1) += 3 n-1 over n^-n

Hope this helps

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