Answer:
[tex] x_1 = 2 [/tex]
[tex] x_2 = -10 [/tex]
Step-by-step explanation:
To find all of the zeros of f(x) = 5x^2 + 40x - 100 we can use the quadratic formula:
[tex]x = \frac{-40 \pm \sqrt{40^2 - 4(5)(-100)}}{2(5)}[/tex]
[tex]x = \frac{-40 \pm 60}{10}[/tex]
[tex]x_1 = \frac{-40 + 60}{10}[/tex]
[tex] x_1 = 2 [/tex]
[tex]x_2 = \frac{-40 - 60}{10}[/tex]
[tex] x_2 = -10 [/tex]
