andrewli86
andrewli86 andrewli86
  • 19-05-2017
  • Mathematics
contestada

find the dimensions of a rectangle whose perimeter is 42 m and whose area is 104 m squared

Respuesta :

Аноним Аноним
  • 19-05-2017
P=42 m
1/2 of P=21
1/2 of P= l+w
21=13+8
A=13×8
A=104 m^2. As a result, the length is 13 m, and the width is 8 m. Hope it help!
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