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With a fair die, the probability of rolling any number 1 through 6 is the same.
If P(1) represents the probability of rolling a 1, P(2) the probability of rolling a 2, and so forth, what is the value of: P(1) + P(2) + P(3) + P(4) + P(5) + P(6)

Respuesta :

irspow
The probability of all possible outcomes is always 1, meaning 100%.

In this case the probability of rolling a 1,2,3,4,5, or 6 is:

1/6+1/6+1/6+1/6+1/6+1/6

6(1/6)

6/6

1
P(any number from 1 to 6) = 1/6

so the sum of P(1) + P(2) etc is  6*1/6 = 1

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