peanutswift5575 peanutswift5575
  • 20-06-2017
  • Chemistry
contestada

Find the pH of a 0.310 M aqueous benzoic acid solution. For benzoic acid, Ka=6.5⋅10−5.

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dec77cat dec77cat
  • 20-06-2017
C=0.310 mol/L
Ka=6.5·10⁻⁵

pH=-lg√(C·Ka)

pH=-lg√(0.310·6.5·10⁻⁵)=2.35
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