QueenJahaida
QueenJahaida
20-07-2017
Mathematics
contestada
help me please!! !!!!!!!!!!!!!!
Respuesta :
koziadam
koziadam
20-07-2017
Challenge accepted.
CE / 2 = 3JQ / 7
7(CE) = 2(3JQ)
7CE = 6JQ
/6Q /6Q
7CE
/6Q = J
Answer is A. I ain't fully sure cuz I'm only in grade 9 lol
Answer Link
Banabanana
Banabanana
20-07-2017
[tex] \frac{CE}{2}= \frac{3JQ}{7} \\ \\7CE= 2*3JQ \\ \\ 7CE= 6JQ \\ \\ J= \frac{7EC}{6Q} [/tex]
Answer Link
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