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17-08-2017
Mathematics

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Find the least number between 200 and 500 which leaves a reminder of 3 in each case when divide by 8,10,12 and 30

Respuesta :

17-08-2017

Hello,

Assume n the number to be found.
n-3 is so a multiple of 8,10,12,30 .
The lcm of 8,10,12,30 is 2^3*3*5=120

n-3=120 or 240 or 360.... n-3=240
==> n=243

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