Respuesta :

[tex] \cfrac{ \frac{1}{9}- \frac{1}{x} }{ \frac{1}{81} - \frac{1}{x^2} }= \cfrac{ \frac{x-9}{9x} }{ \frac{x^2-81}{81x^2} }= \cfrac{x-9}{9x}* \cfrac{81x^2}{(x-9)(x+9)}= \cfrac{9x}{x+9} [/tex]