kaylaanderson1658 kaylaanderson1658
  • 20-08-2017
  • Mathematics
contestada

The length of a rectangle is 5 feet longer than its width. if the perimeter of the rectangle is 50 feet, find its area.

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backseatdog
backseatdog backseatdog
  • 20-08-2017
Let L be length and W be width.

L = 5 + W
So the perimeter is equal to 2L + 2W and that equals 50 feet.

So substitute L with 5 + W to get:

2(5+W) + 2W = 50
10 +2W + 2W = 50
10 + 4W = 50
4W = 40
W = 10
Which means:
L = 15

So the area is just LxW which is 15x10 = 150 feet squared
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