Respuesta :
To solve this problem, we can use the combined gas law, which states that the ratio of the product of pressure and volume to the absolute temperature is constant for a given amount of gas.
The combined gas law equation is:
(P1V1) / T1 = (P2V2) / T2
Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature (in Kelvin)
P2 = final pressure
V2 = final volume
T2 = final temperature (in Kelvin)
First, we need to convert the temperatures from Celsius to Kelvin:
Initial temperature T1 = 20°C + 273 = 293K
Final temperature T2 = 0°C + 273 = 273K
Now we can plug in the values into the combined gas law equation:
(1520 mmHg * 700 mL) / 293K = (P2 * 450 mL) / 273K
Solving for P2:
(1064000 mmHg mL) / 293 = (P2 * 450) / 273
P2 = (1064000 * 450) / (293 * 273)
P2 = 68940000 / 79809
P2 ≈ 863.95 mmHg
Therefore, the final pressure of the gas when the final volume is 450 mL at 0°C is approximately 863.95 mmHg.
The combined gas law equation is:
(P1V1) / T1 = (P2V2) / T2
Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature (in Kelvin)
P2 = final pressure
V2 = final volume
T2 = final temperature (in Kelvin)
First, we need to convert the temperatures from Celsius to Kelvin:
Initial temperature T1 = 20°C + 273 = 293K
Final temperature T2 = 0°C + 273 = 273K
Now we can plug in the values into the combined gas law equation:
(1520 mmHg * 700 mL) / 293K = (P2 * 450 mL) / 273K
Solving for P2:
(1064000 mmHg mL) / 293 = (P2 * 450) / 273
P2 = (1064000 * 450) / (293 * 273)
P2 = 68940000 / 79809
P2 ≈ 863.95 mmHg
Therefore, the final pressure of the gas when the final volume is 450 mL at 0°C is approximately 863.95 mmHg.
