Respuesta :

shinmin

Given:


Mean – 385 per ticket


Standard Deviation - 110


P (Z > x ) = 0.03
Value of z to the cumulative probability of 0.03 from the normal distribution table is 1.88


P(x-u / (standard deviation) > x - 385/110) = 0.03

That is, (x - 385/110) = 1.88

Therefore, x = 1.88 * 110+385 = 591.91 or $592

meerkat18
P ( Z > x ) = 0.03Value of z to the cumulative probability of 0.03 from normal table is 1.88P( x-u/ (s.d) > x - 385/110) = 0.03That is, ( x - 385/110) = 1.88--> x = 1.88 * 110+385 = 591.91
Round off= $592

Otras preguntas