Answer:
[tex]-14jk[/tex]
Step-by-step explanation:
We are asked to find the quotient of our given expression [tex]42j^4k^2\div -3j^3k[/tex]
First of all, we will write our given problem as a fraction.
[tex]\frac{42j^4k^2}{-3j^3k}[/tex]
Using exponent property [tex]\frac{a^m}{a^n}=a^{m-n}[/tex], we will get:
[tex]\frac{42}{-3}(j^{4-3}k^{2-1})[/tex]
[tex]-14j^{1}k^{1}[/tex]
[tex]-14jk[/tex]
Therefore, the quotient of our given problem is [tex]-14jk[/tex].
