2 pipes running together can fill a cistern in 3 1÷3 min.if one pipe takes 3 min more than the other to fill it,find the time in which each pipe would fill the cistern
It takes one pipe x minutes, the other pipe x+3 minutes the portion filled per minute is by one pipe is 1/x, by the second pipe 1/(x+3)
when two pipes running together: 3&1/3[1/x+1/(x+3)] =1, 1 means the whole cistern solve for x: 3&1/3(x+3) +3 1/3(x)=x(x+3) 6 &2/3 x +10 =x^2+3x x^2- (3&2/3) x-10=0 3x^2-11x-30=0
this cannot be factored, so use the quadratic equation: x is about 5.5 x+3=8.5
