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dwh2o13
B,C, and E are correct:

Recall sin Θ = opp/hyp cos Θ = adj/hyp and tan Θ = opp/adj
check the first picture below, that's just an example of the correspondence of those two angles in a right-triangle, notice, the cosine of one is the sine of the other.

now, keeping in mind that 

[tex]\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad\qquad cos(\theta)=\cfrac{adjacent}{hypotenuse} \\\\\\ % tangent tan(\theta)=\cfrac{opposite}{adjacent}[/tex]

check the second picture below.
Ver imagen jdoe0001
Ver imagen jdoe0001

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