Answer:
1.67 M
Explanation:
Molarity = [tex]\frac{moles}{liter}[/tex]
Moles = [tex]\frac{mass}{molar mass}[/tex]
Given
Mass of KOH = 14 g
Molar mass of KOH = 56.1056 g/mol
Moles of KOH = [tex]\frac{14 g}{56.1056 g/mol}[/tex] = 0.25 mol
Volume of solution = 150 ml = 0.15 L (1 L = 1000 ml)
Molarity = [tex]\frac{0.25 mol}{0.15 L }[/tex]= 1.67 M
