okegbewilfred22 okegbewilfred22
  • 21-02-2018
  • Mathematics
contestada

tanA+tanB=sin(A+B)/cosAcosB

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SatansGF
SatansGF SatansGF
  • 21-02-2018
Do you need to prove that it is equal?
If so:

SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA)/cosAcosB

(SinAcosB + sinBcosA)/cosAcosB = (SinAcosB + sinBcosA)/cosAcosB

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