BABA6392 BABA6392

16-03-2018
Physics

contestada

If the change in enthalpy is -5074.1 kj , how much work is done during the combustion?

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fastcamryn fastcamryn

16-03-2018

Hence,
∆H = ∆U + W
=>
W = ∆H - ∆U
= -5074 kJ - (-5084.) kJ
= 10 kJ

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