celeste121
celeste121 celeste121
  • 20-03-2018
  • Mathematics
contestada

use the quadratic formula to solve 5x=6x^2-3, what are the values of x?

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wolf1728
wolf1728 wolf1728
  • 20-03-2018
5x= 6x^2 -3
6x^2 -5x -3
a = 6
b = -5
c = -3

x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +-
sq root (25 -(4*6*-3)] / 12
x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +-
9.84886] / 12
x1 =
1.237405  
x2 =
-0.404072



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