Respuesta :
[tex](2x + 1)(3x - 8) \\ 6x {}^{2} - 16x + 3x - 8 \\ 6x {}^{2} - 13x - 8[/tex]
(2x+1)(3x-8)
To write it in expanded form we use FOIL method
FOIL ----> First Outer Inner Last
First = 2x * 3x = [tex] 6x^2 [/tex]
Outer = 2x * -8 = -16x
Inner = 1 * 3x = 3x
Last = 1 * -8 = -8
Now write all the terms in order
[tex] 6x^2 - 16x + 3x -8 [/tex]
Combine like terms
[tex] 6x^2 - 13x -8 [/tex]
