noobk18p4h6m4
noobk18p4h6m4 noobk18p4h6m4
  • 19-04-2018
  • Mathematics
contestada

standard normal curve between z=.42 and z=1.92
a= .6902
b= .3098
c= .1902
d= .8098

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MrEquation
MrEquation MrEquation
  • 29-04-2018
The correct answer is Choice B: 0.3098.

To find the answer, you have to use a normal distribution table. Look up the percents for each z-score and subtract them to find the region between.

z = 1.92 the percent is 0.9726

z = 0.42 the percent is 0.6628

0.9726 - 0.6628 = 0.3098
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