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21-03-2017
Chemistry

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How many liters will 451 g of krypton gas occupy at STP

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ChronicA ChronicA

21-03-2017

First divide 451g by kryptons molar mass
451g/84gmol= 5.369047619moles

Then multiply 5.369047619moles by 22.4L(volume 1 mol of a gas occupies at STP)

5.369047619moles x 22.4L= 120.26L

Answer: 120.26L

Hoped this helped to explain molar conversions it can be hard to understand at first but you will get the hang of it

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